the present population of a certain place is 67205 the population growth rate is 5% per annum find the population of that place a year before

Let P be the population two years ago.

∴ P(1+

100

5

)

2

=104832

P(

100

105

)

2

=104832

P×

100

105

×

100

105

=104832

P=

105×105

104832×100×100

=95085.71

=95,086 (rounding off to the nearest whole number)

∴ Two years ago the population was 95,086.

Step-by-step explanation:

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https://youtu.be/PkKnp4SdE-w

Step-by-step explanation:

∴ P(1+

100

5

)

2

=104832

P(

100

105

)

2

=104832

P×

100

105

×

100

105

=104832

P=

105×105

104832×100×100

=95085.71

=95,086 (rounding off to the nearest whole number)

∴ Two years ago the population was 95,086.

the first one is x^2+2x+2

the second one is x^2+4

the last one is x^2-4x+8