Excuse the work I’ve already done but I cannot seem to get the right answer. I’m getting 3.5 for the fries and 12.55 for the pizzas.

Step-by-step explanation:

set pizzas as x, set french fries as y

5x + 2y = 73.25

and

2x + y = 30

y= -2x + 30

sub y = -2x + 30 into 5x + 2y = 73.25

5x + 2(-2x+30) = 73.25

5x - 4x + 60 = 73.25

x = 13.25

2(13.25) + y = 30

26.5 + y = 30

y = 3.5

6 pizzas and 4 french fries.

6(13.25) + 4(3.5)

= 79.5 + 14

= 93.5

100 < 93.5

Therefore, Lynn has enough budgets to buy 6 pizzas and 4 french fries.

the median here is 25. your lowest value is 14 and highest value is 48. to find the third quartile, find the medium number in between 25 and 48 which would be 42 i believe.