Rationalise the denominator of: (√3 - √2)/(√3+√2) = ?

Step-by-step explanation:

(√3-√2)/(√3+√2)

Rationalised form = ?

Given that

(√3-√2)/(√3+√2)

The denominator = √3+√2

The Rationalising factor of √3+√2 is √3-√2

On Rationalising the denominator then

=> [(√3-√2)/(√3+√2)]×[(√3-√2)/(√3-√2)]

=> [(√3-√2)(√3-√2)]×[(√3+√2)(√3-√2)]

=> (√3-√2)²/[(√3+√2)(√3-√2)]

=> (√3-√2)²/[(√3)²-(√2)²]

Since (a+b)(a-b) = a²-b²

Where , a = √3 and b = √2

=> (√3-√2)²/(3-2)

=> (√3-√2)²/1

=> (√3-√2)²

=> (√3)²-2(√3)(√2)+(√2)²

Since , (a-b)² = a²-2ab+b²

Where , a = √3 and b = √2

=> 3-2√6+2

=> 5-2√6

Hence, the denominator is rationalised.

Rationalised form of (√3-√2)/(√3+√2) is 5 - 2√6.

answer: my brother can figure it out, imma go get him so i can answer : ) edit: my brother is sleeping, sorry man

step-by-step explanation:

the solution is x=1

step-by-step explanation:

we are given our   equation as

let's assume

left side function is

right side function is

now, we can draw graph

and then we can get intersection point

the intersection point will be solution

so, the solution is

x=1