4x^2-4x-3=0 in standard form

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  4x^2-4x-3=0

Step-by-step explanation:

The equation is in standard form. No change is required.

  4x^2-4x-3=0

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Additional comment

In some parts of the world, a quadratic is said to be in "standard form" if it is written in vertex form. That would be ...

  4(x^2 -x) -3 = 0

  4(x^2 -x +1/4) -3 -4(1/4) = 0 . . . . add and subtract 4(1/4)

  4(x -1/2)^2 -4 = 0 . . . . . the other "standard form"

not solvable

step-by-step explanation:

we need more information, or at least an

93.8

step-by-step explanation:

lets say, first number = x

second number = 3x+7

total = 49

(x)+(3x+7)= 49

4x+7 = 49

4x = 42

x = 42/4

x= 10.5

x= 10.5

3x+7 = 3(10.5)+7 = 93.8

hope this