the length of the rectangle is 5 yards more than twice the width and the area of the rectangle is 63 yards squared what is the length what is the width

Step-by-step explanation:

L = 2W + 5

A = LW = 63

L = 63/W

W=63/L

L = 2W + 5

63/W = 2W + 5

63 = 2WW + 5W

2WW + 5W - 63 = 0

2WW + 5W - 63 = 0

is already in quadratic equation form: ax^2 + bx + c = 0

use the quadratic formula to solve for two solutions:

x = ( -b +- sqrt( bb - 4ac ) ) / 2a

the two solutions are:

x = 9/2

x = -7

you cant have a negative solution for length so use the positive one

solve for length:

L=5+2(9/2)

L=5+18/2

L=5+9

L=14

7. d. 64

8. i. 32

9. c. 125

10. j. none of the above

11. d. 81

12. i. 216

13. e. none of the above

14. g. 240

15. e. none of the above

16. g. 32

17.   e. none of the above

1. minimum

2. 6400

3. eight

hope this !