A function of the form f(x) = ab' is modified so that the b value remains the same but the a value is increased by 2 How do the domain and range of the new function compare to the domain and range of the original function? Check all
that apply.
The range stays the same.
The range becomes y> 2.
The domain stays the same.
The domain becomes x > 2.
The range becomes y 2 2.
The domain becomes x 2 2.

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

if you was gonna solve for a, a is a   < -12

if im not mistaking its

step-by-step explanation: