We say that a triangle is angle-almost-equilateral error e> 0 if the absolute value of the difference between each of its angles and 60° is less than e. Show that for every e> 0 there are angle-almost-equilateral error triangles e whose vertices have integer coordinates in the Cartesian plane. From among all the triangles with these properties, determine the one with the smallest area.

the answer is 510

step-by-step explanation:

15 • 13 = 195

15 • 12 = 180

15 • 5 = 75

12 • 5 = 60

195 + 180 = 375

375 + 75 = 450

450 + 60 = 510

no, the equation would be invalid since they are both not equal.

step-by-step explanation:

here you got

4y-6+4y 2-9

first, you would simplify the equation on the form.

4y-6+4y 2-9

then, move all the terms that contains a y to the left and all the other terms to the right.

+4y-4y+-9-6

finally, you will simplify the left and the right side of the equation.

y=-3

stethere all not eveanp-by-step explanation: