Triangle Proofs
Prove that triangle ABE is congruent to triangle CDE

Step-by-step explanation:

considering, ∆ABE and ∆ CDE.

(I) BE=DE (S),

(II) AE=EC (S),

(III) <AEB=<CED (Vertically opposite angle) [A].

So, by A.A.S. criterion we can prove that ∆ABE~=∆CDE.

hope my answer helps you.

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.