A truck's position relative to a car's position is- 60 feet. The car and the truck move
in the same direction, but the car moves 5 feet
per second faster for 8 seconds, What operations
could be used to find the trucks relative position
after 8 seconds? Explain

The truck's relative position with respect to the car is: -100 feet

Step-by-step explanation:

If the truck is moving at a seed "V" then its position after 8 seconds is going to be:

XT = V* t = V * 8 = 8 V

The car, which is initially 60 feet ahead of the truck and starts moving at 5 m/s faster than the truck, would have a speed given by: V + 5

And its position (relative to the truck's) would be:

XC = 60 + (V + 5) * t = 60 + (V + 5) * 8 = 60 + 40 + 8 V = 100ft + 8 V

then the position of the truck relative to that of the car would be given by the difference:

XT - XC = 8 V - (100 +8 V) = 8 V - 8 V - 100ft = -100 feet

38.5

step-by-step explanation:

lets say, first number = r

second number = 3r+7

total = 49

(r)+(3r+7)= 49

4r+7 = 49

4r = 42

r = 42/4

r= 10.5

3r+7 = 3(10.5)+7 = 38.5

hope this

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