Write an equation of the line. The line passes through point (0,-3) an is parallel to a line with slope 1.2. Also write an equation for the line. The line passes through point (4,0) and has slope .5

Hello,

Two parallel lines have the same slope, which means that our line's slope, will also be 1.2.

So now we have a point and a slope, so we can use the following formula to find the equation of the line:

y-y1 = m (x-x1)

Where:

y1 - y coordinate of a point on the line

x1 - x coordinate of the same point on the line

m - slope

Plugging in we get:

y+3 = 1.2 (x-0)

y = 1.2x - 3 (slope intercept form)

or

5y-6x = -15 (standard form)

1.  y = 1.2x - 3

2.  y = 0.5x - 2

the full equation is y = 0.5x - 2

Step-by-step explanation:

Case 1:  Since both the y-intercept and the slope are given, we can immediately write out the equation of this line, beginning with the slope-intercept equation y = mx + b:

y = 1.2x - 3

Case 2:  Again starting with y = mx + b:  Substitute 4 for x, 0 for y and 0.5 for m and calculate b:

0 = 0.5(4) + b, or

0 = 2 + b

Then b = -2, and the full equation is y = 0.5x - 2

b. 24 mm

step-by-step explanation:

use the pythagorean theorem.

a^2 + b^2 = c^2

a^2 + 7^2 = 25^2

a^2 + 49 = 625

a^2 = 576

a = 24

answer: b. 24 mm

-13

step-by-step explanation:

f(x)=2x-5 for f(-4)

f(-4)   means let x=-4

f(-4) = 2(-4) -5

f(-4) =-8-5

      = -13