Ameera, Maria and David have a combined weight of 63 kilograms.
David weighs 8 more kilograms than
Maria and Ameera weighs 2 more
kilograms than David. How much does
each child weigh?
What is the step by step process for that answer

Ameera = 25 kg

Maria = 15 kg

David = 23 kg

Step-by-step explanation:

Let:

A = Ameera Weight

M = Maria Weight

D = David Weight

Create equations to compare the children's weights:

D = 8 + M

A = 2 + D

63 = D + A + M

Solve simultaneous equations:

Substitute A = 2 + D

63 = M + 2 + D + D

63 = M + 2 + 2D

Now substitute D = 8 + M

63 = M + 2 + 2(8 + M)

63 = 3M + 18

Solve for M

Therefore M = 50/3

Maria weighs 16.67 kg!

Substitute M = 15 into D = 8 + M

D = 8 + 15

D = 23

David weighs 23 kg!

Substitute D = 23 into A = 2 + D

A = 2 + 23

A = 25

Ameera weighs 25 kg!

step-by-step explanation:

d is the correct answer

step-by-step explanation:

x= 8 because 3x = 3 * 8, and 3*8 = 24