Solve the system of equations -2x-4y=-8−2x−4y=−8 and 7x+5y=-177x+5y=−17 by combining the equations. \big( -2x(−2x -4y−4y == -8\big)−8)
\big( 7x(7x +5y+5y == -17\big)−17)
-2x−2x -4y−4y == -8−8
7x7x +5y+5y == -17−17
0
0xx ++
0
0yy ==

(from deltha math) HELP

yes because a quadrilateral is equal to 4 sides and a rhombus has 4 sides so technacly it is a quadrilateral.

simplifying

5(x + -6) = 2(x + 3)

reorder the terms:

5(-6 + x) = 2(x + 3)

(-6 * 5 + x * 5) = 2(x + 3)

(-30 + 5x) = 2(x + 3)

reorder the terms:

-30 + 5x = 2(3 + x)

-30 + 5x = (3 * 2 + x * 2)

-30 + 5x = (6 + 2x)

solving

-30 + 5x = 6 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-30 + 5x + -2x = 6 + 2x + -2x

combine like terms: 5x + -2x = 3x

-30 + 3x = 6 + 2x + -2x

combine like terms: 2x + -2x = 0

-30 + 3x = 6 + 0

-30 + 3x = 6

add '30' to each side of the equation.

-30 + 30 + 3x = 6 + 30

combine like terms: -30 + 30 = 0

0 + 3x = 6 + 30

3x = 6 + 30

combine like terms: 6 + 30 = 36

3x = 36

divide each side by '3'.

x = 12

simplifying

x = 12

this should .

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step-by-step explanation:

where is the question is there is a formula or is there not one