33. When slam-dunking, a basketball player seems to hang in the air at the height of his jump. The height h(t), in feet above the ground, of a basketball player at time t, in seconds since the start of a jump, is given by
h(t) = -16t² + 16Tt,
where T is the total time in seconds that it takes to complete the jump. For a jump that takes 1 second to complete, how much of this time does the basketball player spend at the top 25% of the trajectory? (Hint: Find the
maximum height reached. Then find the times at which the height is 75% of this maximum.]