Although a football field appears to be flat, some are actually shaped like a parabola so that rain runs off to both sides. The cross section of a field can be modeled by y = -0.000234x (20 160), where x and y are measured in feet. What is the width of the field? What is the maximum height of the surface of the field? Round your answers to the nearest tenth, if necessary. The width of the field is feet. The maximum height of the field is about fleet.

The ends of the field are at the zeros (x-intercept) of the function.

0 = -0.000234(x - 80)2 + 1.5      subtract 1.5 from both sides

-1.5 = -0.000234(x - 80)2           divide both sides by right coefficient

6410.25641 = (x - 80)2              take square root of both sides

80.064 = x - 80                         add 8-0 to both sides

160.064 = x

The field is 160.064 feet wide.  

The maximum is at the vertex, y = 1.5 feet

Step-by-step explanation:

so what is the question

step-by-step explanation:

area = length x width

length = 2 x width

32 = 2 x width x width

32 = 2 x width^2

36 = width ^2  

width = 6

length = 12

area is 32

perimeter = 2 x 12 + 2 x 6 = 24 + 12 = 36

step-by-step explanation: