A square and a rectangle have the same perimeter is the length of the side of the square is 4X minusone the score of the rectangle is 2X + 2 and the width is 2X right and solve an equation to find X

Square Perimeter = 4(4x-1)

Rectangle Perimeter = 2(2x+1) + 2(x+2)

Square Perimeter = Rectangle Perimeter

4(4x-1) = 2(2x+1) + 2(x+2)

16x - 4 = 4x + 2 + 2x + 4

16x - 4 = 6x + 6

-6x +4 -6x +4

10x = 10

x = 1

8

step-by-step explanation:

-362

step-by-step explanation:

(12)(4)+2(12)-34(12)+2(12)-3

  \/         \/         \/         \/

  48 +   24 -   408 + 24 - 3

      \   /               \   /

          72     -     432 - 3 = -363