Given that y varies inversely as x^2 and that y = 2, when x = 4. Calculate the value of y when x = 5.

where is the rest of the

step-by-step explanation:

step-by-step explanation:

hello from mrbilldoesmath!

answer:

(7 x + 6 y) (49 x^2 - 42 x y + 36 y^2)

discussion:

the trick is to recognize that 343 = 7^3 and 216 = 6^3 and, in general,

a^3 + b^3 =   (a + b) (a^2 - a b + b^2).

in our case

343x^3+216y^3   =   (7x)^3 + (6y)^3

so take a = 7x and b = 6y in the above equation to get the answer.

you,

mrb

i love jeffery and believe there is truth in tati and james' answers

step-by-step explanation:

yes i have heard the tea

i believe both

no, tati didnt over exaggerate

james might might idk and tbh dont rly care