(sin thetha - cos thetha) whole square = 1-2sin thetha • cos thetha​

see explanation

Step-by-step explanation:

Using the identity

sin²x + cos²x = 1

Consider the left side

(sinθ - cosθ)² ← expand using FOIL

= sin²θ - 2sinθcosθ + cos²θ

= 1 - 2sinθcosθ

= right side , thus verified

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine

step-by-step explanation:

i found the koficent of the linear function and i foun c acordind to the strict formula y=kx+c and then i took 2 as an x and replacet it on the formula i found and then foun the y