A small stone is thrown vertically upwards from a point A above the ground. At time t secs after being thrown from A, the height of the stone above the

ground is s metres. Until the stone hits the ground, s = 1.4 +19.6t- 4.9t²

(a) Write down the height of A above the ground.

(b) Find the speed with which the stone was thrown from A.

(c) Find the acceleration of the stone until it hits the ground

5/6

step-by-step explanation:

if i remember correctly with perpendicular stuff you just take away the negative

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explanation

the graph has a slope of 1/3 because each time you move up 1, you go to the right 3. so, slope = rise/run = 1/3. we can cross choice a off the list since we want a slope of 3, rather than 1/3.

the first table shown has a slope of -3. this is because the rise is -6 and the run is 2, so slope = rise/run = -6/2 = -3. note how x increases by 2 each time (run) and y drops by 6 each time (rise). choice b can be eliminated.

the second table has a slope of 3. each time x goes up by 1, the y values increase by 3. slope = rise/run = 3/1 = 3. alternatively you can use the slope formula to prove that the slope is 3 here. use any two rows of values to generate the two points. choice c is one of the answers

the third table also has a slope of 3. let's use the slope formula to prove as such. i'm going to use the first two rows of the table. so i'll use the two points (2,1) and (5,10)

m = slope

m = (y2-y1)/(x2-x1)

m = (10-1)/(5-2)

m = 9/3

m = 3 so we get a slope of 3

choice d is the other answer

it's both, now can you answer my most recent question?