1. Use the given frequency distribution to find the a) Class width.
b) Midpoint of the first class.
c) Class boundaries of the first class.
d) Relative frequency of the first class
Class Frequency, f
50 – 52
53 – 55
56 – 58
59 – 61
62 - 64
8
15
12
10
5

0.5 meters per second

step-by-step explanation:

the average speed between 2 seconds and 8 seconds is 0.5 meters per second.

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step-by-step explanation:

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(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180