Question 3: Find d^2y / dx^2 for y=4x^4−3x^3−6x^2+x A d^2y / dx^2v = 16x^3−9x^2−12x+1

B d^2y / dx^2 = 16x^2−9x−12

C d^2y / dx^2 = 48x^2−18x−12

D d^2y / dx^2 = 8x^2−6x−8

idk

step-by-step explanation:

think the answer would beb

hello from mrbilldoesmath!

answer:

(7 x + 6 y) (49 x^2 - 42 x y + 36 y^2)

discussion:

the trick is to recognize that 343 = 7^3 and 216 = 6^3 and, in general,

a^3 + b^3 =   (a + b) (a^2 - a b + b^2).

in our case

343x^3+216y^3   =   (7x)^3 + (6y)^3

so take a = 7x and b = 6y in the above equation to get the answer.

you,

mrb