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An approximate solution to an equation is found using this iterative process. (x, )' – 1 Xp+1 = and x, = -1 4 a) (i) Work out the value of x, (ii) Work out the value of x, b) Work out the solution to 6 decimal places.
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An approximate solution to an equation is found using this iterative process.
(x, )' – 1 Xp+1 = an...
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