A triangular frame has sides that measure 15'-7",20'-4" and 26'-2". What is the total length of three sides?

The total length of three sides is 62'-1"

Step-by-step explanation:

We know that 1 foot = 12 inches and 1' = 12''

Part 1)

We also know that side 1=15'-7", side 2=20'-4", side 3=26'-2"

To find the total length of three sides sum the three sides

So the total length=side 1+side 2 +side 3

Now we substitute

Total length=15'-7"+20'-4"+26'-2"

Total length=(15'+20'+26')+(7"+4"+2")

Total length=(61')+(13")

Remember that 12"=1'

13"=12"+1"=1'+1"

Substitute again

Total length=(61')+(1'+1")

Total length=(62')+(1")> 62'-1"

Therefore the answer is the total length of three sides is 62'-1"

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step-by-step explanation:

1699/ 8548

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl