2secx=1/1-sinx+1/1+sinx​

Below in bold.

Step-by-step explanation:

1/(1 - sin x) + 1/(1 + sinx)

= (1 + sin x + (1 - sin x) ) / 1 - sin^2 x

= 2 / (1 - sin^2 x)

= 2 / (cos^2 x)

= 2 sec^2 x

So 2 sec x = 2 sec^2 x

sec^2 x - sec x = 0

sec x(sec x - 1) = 0

giving sec x =0 or sec x = 1.

sec x cannot be 0 so sec x = 1

this gives x = 0 , 360 degrees  ( where 0 =< x <= 360)

a 270° rotation about point p says on e d g e n u it y (had to space it out because it says it's a misspelling so i couldn't submit it