he first four terms of the expansion of the binomial ( 2 ⁢ x 3 + 3 ⁢ y 2 ) 7 are shown. 128 ⁢ x 21 + 1 , 344 ⁢ x 18 ⁢ y 2 + 6 , 048 ⁢ x 15 ⁢ y 4 + 15 , 120 ⁢ x 12 ⁢ y 6 + ⋯ Complete the last four terms by dragging the missing values to the correct locations in the expression. Not all values will be used.

step-by-step explanation:

ok so im not 100% sure but you would start by adding 5.1t and 1.9t beacuse they have the same variable. that is 7t.   then add -3.6 + 1.2 which is -2.4

so then keep that as -2.4 + 7t. i apologize if this is incorrect. best luck on your test < 3

4 candies

step-by-step explanation:

7 x 28 = 196

200 - 196 = 4 candies remaining.

a and c

for infinitely many solutions we require both left and right sides to be equal

distribute and simplify

a

14 - 8x = 20 - 8x - 6 = 14 - 8x ← both sides equal so infinite solutions

b

6x - 54 = 6x - 54 + x = 7x - 54 ← not equal

c

4x + 16 = 4x + 10 + 6 = 4x + 16 ← both sides equal so infinite solutions

d

5x - 40 + 10 = 5x + 10

5x - 30 = 5x + 10 ← not equal

yes, whats the problem?