What is the completely factored form of this polynomial? A+ 12x2 + 32
A. (x2 + 4)(x + 2)(x+4)
O B. (x2 + 4)(x2 + 8)
OC. (x + 4)(X + 8)
OD.
(x + 2)(x-2)(x2 + 8)

The answer will be (x^2 + 4)(x^2 + 8)

By factoring out your equation you get:

(x^4 + 8x^2)(4x^2 + 32)

This is because when solving you want something that adds to the B value and also multiplies to our A•C value.

Factoring out each group gives us:

x^2(x^2 + 8) +4(x^2 + 8)

Then after that we will have our completely factored problem:

(x^2 + 4) and (x^2 + 8)