Given a*b = 3a²b, determine: a) (2*1) b) (2*1) *3 2. Given n#m = √3mn, determine a) 2#6 b) (4#3) #2 ​

1a)12 b)1296 2a)6 b)6

Step-by-step explanation:

1a)a*b=3a^2b

(2*1)=3*2^2*1

=3*4*1

=12.

b)(2*1)*3=12*3

=3*12^2*3

=3*144*3

=1296.

2a)n#m=√3mn

2#6=√3*2*6

=√36

=6.

b)(4#3)#2

(4#3)=√3*4*3

=√36

=6

6#2= √3*6*2

= √36

=6

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204