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Mathematics, 18.09.2021 16:30 fake7667

Solve the following equation for xx. 5(2x+3)-7=-2(x+2)5(2x+3)βˆ’7=βˆ’2(x+2)< br />
x=-1/3x=βˆ’1/3

x=1/2x=1/2

x=3x=3

x=-1x=βˆ’1

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Solve the following equation for xx. 5(2x+3)-7=-2(x+2)5(2x+3)βˆ’7=βˆ’2(x+2)< br />
x=-1/3x=βˆ’1/3...
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