two angles are supplementary if the sum of their measures is 180 degress. Find two supplementary angles such that the larger angle is 76 degrees more than 2 times the smaller angle.

Step-by-step explanation

larger angle = 76+2x

smaller angle = x

supplementary angles add up to 180

∴(76+2x)+x=180

76+3x=180

3x= 180-76

3x = 104

x = 104/3

x = 34.7°(smaller angle)≈ 35

larger angle = 76+2(34.7)

=76+69.4

=145.4≈ 145

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b