A faulty watch gains 10 seconds an hour. If it is set correctly at 8pm one evening what time will it show when the correct time is 8pm The following evening

or

step-by-step explanation:

we need to solve for 'x' the following equation:  

we have that:

⇒

⇒ ⇒

factorizing, we get that:

  ⇒

then, the solutions are: or

nothing extraneous has been found!

the answer is 1030 it's very simple math.

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