Factor out 8x^3 y^2 - 6x^2 y + 2xy^2

2xy • (4x2y + 3x - 1 )

Step-by-step explanation:STEP

1

:

Equation at the end of step 1

 (((8•(x3))•(y2))+((2•3x2)•y))-2xy

STEP

2

:

Equation at the end of step

2

:

 ((23x3 • y2) +  (2•3x2y)) -  2xy

STEP

3

:

STEP

4

:

Pulling out like terms

4.1     Pull out like factors :

  8x3y2 + 6x2y - 2xy  =   2xy • (4x2y + 3x - 1)

Trying to factor a multi variable polynomial :

4.2    Factoring    4x2y + 3x - 1

Try to factor this multi-variable trinomial using trial and error

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

step-by-step explanation:

cats