Write the equation of the perpendicular bisector of AB if A(-6, -4) and B (2,0).

Step-by-step explanation:

Long way:

Find the midpoint (M) of AB, find the slope(m) of the line AB, then find the equation of the line through M with slope -1/m, which is the perpendicular bisector of AB.

Short way:

The perpendicular bisector of (x₁,y₁) and (x₂,y₂): 2(x₂-x₁)x + 2(y₂-y₁)y = x₂²-x₁²+y₂²-y₁².

Here this is 2(1-(-4))x + 2(6-4)y = 1²-(-4)²+6²-4² which is 10x + 4y = 5.

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!

answer:   2 multiplied by x =24

step-by-step explanation: