HELP NEEDED ASAP PLEASE Write the equation of a sine function that has the given characteristics: Amplitude: 3, Period: 6π

Group of answer choices

Y= -3sin(1/2)(x - π/2)

Y= 2 + 5sin(1/3)(x - π/3)

Y= -2sin(1/2)(x - π/5)

Y= -2 + 3sin(1/3)(x - π/2)

hope this .

r3t40

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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