Consider an object moving with velocity function v(t)=1t+3 for t≥0. Give a geometric argument to show that the distance d travelled between t=x and t=x+1, with x≥0, satisfies the inequality 1x+4

6^2 or 36

step-by-step explanation:

6000n

6×1000n

6×10^3 n

so we need 6n need to be a perfect cube

so n has to be 6^2 so that 6n is 6^3

what i'm saying is if you let n be 6^2 you have 6^3×10^3 or 60^3 which is a perfect cube

mr. india

8987678

step-by-step explanation: