If x + 3 is a factor of x3+3x2+ax−12, what is the value of a?

  -4

Step-by-step explanation:

p(x)=x^3+3x^2+ax-12

x+3 is factors means it divide completely so x=-3

p(-3)=(-3)^3+3(-3)^2+a(-3)-12

  -27+27-3a-12=0

 -3a-12=0

3a=-12

a=-12/3

a=-4

-4

Step-by-step explanation:

The most simple is

P(x)=x³+3x²+ax-12

P(-3)=0=(-3)³+3*(-3)²+a*(-3)-12=-3a-12

-3a-12=0

3a=-12

a=-4

u dumb boi

step-by-step explanation:

g = (2, 2)

step-by-step explanation:

given the ratio is 1 : 1 then f is the midpoint of eg

let the coordinates of g = (x, y)

using the midpoint formula

(0 + x) = 1 ( multiply both sides by 2 )

0 + x = 2 ⇒ x = 2

similarly

(4 + y) = 3 ( multiply both sides by 2 )

4 + y = 6 ( subtract 4 from both sides )

y = 2

coordinates of g = (2, 2)