Hi, I need help with this question and I need an explanation pls. Please don't copy the answer from the internet. Here's the question: A ball is thrown into the air from the top of a building. The height, h(t), of the ball above the ground t seconds after it is known can be modeled by
h(t) =-16t²+16t+80. How many seconds after being thrown will the ball hit the ground?

−16(2−−5)

Step-by-step explanation:

hay un factor común entre estos números, por lo que simplemente −16t2+16t+80 divida y reutilice y luego reciba−162+16+80 llegar

−16(2−−5)

v v cj van config k tbs eng r.c r.c fcb fb gb frfr

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length