A projectile is thrown upward so that its distance above the ground after t seconds is h = -16t2 + 608t.
After how many seconds does it reach its maximum height? (5 points)

 19 seconds

Step-by-step explanation:

The maximum height of this parabola will be when the slope of the line hits zero.  Take the first derivative and set it to 0, solve for t.

h = -16t2 + 608t

h' = -32t + 608

32t = 608

t = 19 sec

[The height at 19 seconds is h = -16(19)^2 + 608(19) = 5776 feet

75

step-by-step explanation:

you do x-29=46 (the number of cantaloupes sold)

in order to find x, you have to find what minus 29 equals 46, meaning you'd have to add 29 to 46.

29+46=75

if you replace x with 75, the equation looks like:

75-29=46

x=75

765238725478629038640962136509762139056074

step-by-step explanation:

64087235609746097215074621039754021037