4. A rectangular room is three meters longer than twice the width. If the perimeter of the room is 60 meters, what are the length and width? Set up and solve the problem using an
algebraic equation. Please write a complete sentence answer. (2 points)

The rectangle has a length of 21 meters, and a width of 9 meters.

Step-by-step explanation:

What we know:

- The perimeter is 60 meters

- The length is 3 meters longer than twice the width (2w + 3)

- Width = w

First, we need to set up our equation. Perimeter is the sum of all the sides. So we will add length to length and width to width.

Length: (2w + 3) + (2w + 3) = 4w + 6

Width: w + w = 2w

Now, we add our length and width.

(4w + 6) + (2w) = 6w + 6

Now we solve for w.

6w + 6 = 60

Subtract 6 from both sides.

6w + 6 - 6 = 60 - 6

Simplify.

6w = 54

Divide 6 from both sides.

6w/6 = 54/6

w = 9

The width is 9 meters.

To find the length, we just need to plug in w.

2(9) + 3 =

18 + 3 = 21

The length is 21 meters.

To check our work, we just need to add up all the sides.

9 + 9 + 21 + 21 = 60

x + 4/7

step-by-step explanation:

use cymath