HELP
if a+1 is divisible by 3 prove that 4+7a is divisible by 3 too

Step-by-step explanation:

Assume there exists integer k such that 3k=a+1.

4+7a

=7a+4

=7(a+1)-3

=7(3k)-3

=3(7k-1)

This implies that if there exists integer k such that 3k=a+1 then there is integer 7k-1 such that 3(7k-1)=4+7a

( - 4 , -7 )

all the lines must parallel  

step-by-step explanation:

coordinates of c = ( - 1 , 2 )

3 units left = ( -4 , 2 )

9 units down = ( - 4 , 11 )