Plz help time crunch! Write the slope-intercept form of the equation of the line through the given points.
through: (-3, 6) and (0,5)

 y = -x/3 + 5

Step-by-step explanation:

What we know:

- Our points are (-3, 6) and (0, 5)

First, we need to find the slope. The formula for finding slope is y2 - y1/x2 - x1.

Now, we need to plug in our values.

5 - 6/0 - (-3)

Solve.

-1/3

Our slope is -1/3.

But now we need to find the y-intercept. To do this, we will use the equation y = mx + b.

You can use either coordinate pair, but I will be using (-3, 6) first.

Plug in the values.

6 = -1/3(-3) + b

Simplify.

6 = 1 + b

Subtract 1 to both sides.

6 - 1 = 1 - 1 + b

5 = b

The y-intercept is 5. Now we can put everything together!

y = -1/3x + 5

y = -x/3 + 5

For the coordinate (0, 5), you do the same thing.

5 = -1/3(0) + b

5 = 0 + b

5 = b

y = -1/3x + 5

y = -x/3 + 5

y = -x/3 + 5

Step-by-step explanation:

first we need to find the slope of the line. to find the slope we use the equation (y2 - y1) / (x2-x1) = m ( m is slope)

we can find this from the given 2 points;

y2= 6( highest y value amount these two) and y1 = 5 ( lowest y value amount these two)

now x2 = which is -3 ( since y2 is 6 x2 is -3 its counterpart)

x1 = 0 ( counterpart of y1)

put these in the above equation to find the slope ie;

(y2-y1)/(x2-x1) ; (6-5)/(-3-0) = 1/-3 = -1/3.

now we find the equation of the line;

y2-y1/x2 -x1 = -1/3

for finding the equation you can choose one of the two points that are given as (y1,x2) let's choose the point 0,5. ( you can choose the other point if u like. it doesn't matter.)

now we use the same eqn;

y-5/x-0 = -1/3

y-5/x = -1/3

Y = -x/3 + 5

add 5 subtract 1

step-by-step explanation: