In the quadratic function y=x^2+bx+24, what is the value of the 'b' term which would make the quadratic function factorable?

9514 1404 393

  ±25, ±14, ±11, ±10

Step-by-step explanation:

'b' is the sum of pairs of factors of 24. Those factors are ...

  24 = 1×24 = 2×12 = 3×8 = 4×6

The same product is obtained when both factors are negative. The sums of these pairs are 25,14, 11, 10.

Possible values of b are ±25, ±14, ±11, ±10.

Additional comment

If this is a multiple-choice question, you'd have to see which of your choices matches one of these numbers.

(b): 25,14,11,10,-25,-14,-11,-10

Step-by-step explanation:

24 can be factorized to the following pairs of set: (p,q)    p*q=24  p+q =b

(p,q); (1,24) (2,12) (3,8) (4,6) (-1,-24) (-2,-12) (-3,-8) (-4,-6)

p+q (b): 25,14,11,10,-25,-14,-11,-10

2/3x + 7 = 29

step-by-step explanation:

two thirds = 2/3

plus a number = x

at least 29 = 29

there for you should get 2/3x + 7 = 29

step-by-step explanation:

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