What is the slope of a line perpendicular to the line whose equation is 4x - 5y = 10. Fully simplify your answer. Pls and TYYY

The slope of a line perpendicular to the line whose equation is 4x - 5y = 10 is -5/4.

Step-by-step explanation:

provided the equation;

4x- 5y=10.(let it be equation of line1 )

and the other line be line2

from perpendicularty principle

M1×M2= -1

BUT for M1(slope of line L1)

y= mx+c

where "c" is constant value.

"m" is slope.

therefore

5y= 4x - 10

(dividing by five throughout)

y=(4x/5) - 2

y= (4/5)x - 2

therefore M1= (4/5)

Returning back to our principle

M1×M2= -1

(4/5)M2=-1

M2= -5/4

$25

step-by-step explanation:

25 - 4.50 = 20.5

20.5 / 2 = 10.25

10.25 + 10 = 20.25

20.25 - 12.50 = 7.75

therefore the answer is $25 as shown as the first number.