Given that events A and B are independent with P(A) = 0.25 and P(A and B) = 0.185, determine the value of P(B), rounding to the nearest thousandth, if necessary.​

Step-by-step explanation:

The value of P(A or B) =0.60The value of P(A or B) =0.60Step-by-step explanation:The value of P(A or B) =0.60Step-by-step explanation:Given: A and B are two events.The value of P(A or B) =0.60Step-by-step explanation:Given: A and B are two events.P(A)=0.25 , P(B)=0.5 and P(A and B)=0.15The value of P(A or B) =0.60Step-by-step explanation:Given: A and B are two events.P(A)=0.25 , P(B)=0.5 and P(A and B)=0.15We know that the value of P(A or B) is given by the formula :The value of P(A or B) =0.60Step-by-step explanation:Given: A and B are two events.P(A)=0.25 , P(B)=0.5 and P(A and B)=0.15We know that the value of P(A or B) is given by the formula :\begin{gathered}\text{P(A\ or\ B)}=\text{P(A)+P(B)}-\text{P(A\ and\ B)}Rightarrow\ \text{P(A\ or\ B)}=0.25+0.5-0.15Rightarrow\ \text{P(A\ or\ B)}=0.60\end{gathered} The value of P(A or B) =0.60Step-by-step explanation:Given: A and B are two events.P(A)=0.25 , P(B)=0.5 and P(A and B)=0.15We know that the value of P(A or B) is given by the formula :\begin{gathered}\text{P(A\ or\ B)}=\text{P(A)+P(B)}-\text{P(A\ and\ B)}Rightarrow\ \text{P(A\ or\ B)}=0.25+0.5-0.15Rightarrow\ \text{P(A\ or\ B)}=0.60\end{gathered} P(A or B)=P(A)+P(B)−P(A\ and B)The value of P(A or B) =0.60Step-by-step explanation:Given: A and B are two events.P(A)=0.25 , P(B)=0.5 and P(A and B)=0.15We know that the value of P(A or B) is given by the formula :\begin{gathered}\text{P(A\ or\ B)}=\text{P(A)+P(B)}-\text{P(A\ and\ B)}Rightarrow\ \text{P(A\ or\ B)}=0.25+0.5-0.15Rightarrow\ \text{P(A\ or\ B)}=0.60\end{gathered} P(A or B)=P(A)+P(B)−P(A\ and B)⇒ P(A\ or\ B)=0.25+0.5−0.15The value of P(A or B) =0.60Step-by-step explanation:Given: A and B are two events.P(A)=0.25 , P(B)=0.5 and P(A and B)=0.15We know that the value of P(A or B) is given by the formula :\begin{gathered}\text{P(A\ or\ B)}=\text{P(A)+P(B)}-\text{P(A\ and\ B)}Rightarrow\ \text{P(A\ or\ B)}=0.25+0.5-0.15Rightarrow\ \text{P(A\ or\ B)}=0.60\end{gathered} P(A or B)=P(A)+P(B)−P(A\ and B)⇒ P(A\ or\ B)=0.25+0.5−0.15⇒ P(A\ or\ B)=0.60The value of P(A or B) =0.60Step-by-step explanation:Given: A and B are two events.P(A)=0.25 , P(B)=0.5 and P(A and B)=0.15We know that the value of P(A or B) is given by the formula :\begin{gathered}\text{P(A\ or\ B)}=\text{P(A)+P(B)}-\text{P(A\ and\ B)}Rightarrow\ \text{P(A\ or\ B)}=0.25+0.5-0.15Rightarrow\ \text{P(A\ or\ B)}=0.60\end{gathered} P(A or B)=P(A)+P(B)−P(A\ and B)⇒ P(A\ or\ B)=0.25+0.5−0.15⇒ P(A\ or\ B)=0.60The value of P(A or B) =0.60Step-by-step explanation:Given: A and B are two events.P(A)=0.25 , P(B)=0.5 and P(A and B)=0.15We know that the value of P(A or B) is given by the formula :\begin{gathered}\text{P(A\ or\ B)}=\text{P(A)+P(B)}-\text{P(A\ and\ B)}Rightarrow\ \text{P(A\ or\ B)}=0.25+0.5-0.15Rightarrow\ \text{P(A\ or\ B)}=0.60\end{gathered} P(A or B)=P(A)+P(B)−P(A\ and B)⇒ P(A\ or\ B)=0.25+0.5−0.15⇒ P(A\ or\ B)=0.60 The value of P(A or B) =0.60Step-by-step explanation:Given: A and B are two events.P(A)=0.25 , P(B)=0.5 and P(A and B)=0.15We know that the value of P(A or B) is given by the formula :\begin{gathered}\text{P(A\ or\ B)}=\text{P(A)+P(B)}-\text{P(A\ and\ B)}Rightarrow\ \text{P(A\ or\ B)}=0.25+0.5-0.15Rightarrow\ \text{P(A\ or\ B)}=0.60\end{gathered} P(A or B)=P(A)+P(B)−P(A\ and B)⇒ P(A\ or\ B)=0.25+0.5−0.15⇒ P(A\ or\ B)=0.60 Hence, the value of P(A or B) =0.60

Yes, two vertical lines can be complementary