Solve the compound inequality 6b < 42 or 4b + 12 > 8. b < 6 or b > 5
b < 7 or b > −1
b < 7 or b > 1
b > 6 or b < 5

b<7 or b>-1

Step-by-step explanation:

6b<42

b<7

4b+12>8

4b>-4

b>-1

Therefore, "b<7 or b>-1" is the correct answer

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

the least value out of the data shown is 5, maybe if you post a picture with it i could a little more.

step-by-step explanation: