Construct a random triangle, Δ⁢A⁢B⁢C, and construct the angle bisector of ∠⁢A⁢B⁢C. The angle bisector divides the opposite side, A⁢C¯, into two line segments. Mark the point where the angle bisector intersects A⁢C¯, and label it D. To verify that you have bisect the angle, measure ∠⁢A⁢B⁢D and ∠⁢D⁢B⁢C and display the angle measures. Take a screenshot of your construction, save it, and insert the image below.

3100

step-by-step explanation:

160 cm

step-by-step explanation:

you have to add all the sides together

2 equivalent expressions to represent the area of a rectangle and the top is n-3 and the side is 2

area of the rectangle = length * width

given length = n - 3

width = 2

replace it in the area

so area of the rectangle = (n-3) *2

= 2(n-3)

one of the expression is 2(n-3)

to get another expression we distribute 2 inside the parenthesis

2(n-3) is 2n - 6

so another expression is 2n - 6

two equivalent expression are

2(n - 3)   , 2n - 6