Solve 3x − 2 < 7 or −2x+3<−15

x<3

where x does not exist

(-infinity, 3)

Where x exists

[3, infinity]

Step-by-step explanation:

I'm just going to answer the first one.

Treat it like your solving for x, however the only difference is that it's an inequality.

3x-2 <7

3x< 7+2

3x/3x < 9/3

x<3

Now we know where x does and does not exist.

I'm assuming your teacher wants that, (-infinity, 3) (this is where it does not exist)

[3, infinity]

In case you were wondering square brackets is where it exists and curled is where it doesn't.