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Mathematics, 02.09.2021 21:00 Kimb9820
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Let n be equal to 182% of 60. Which of the following proportions is true?
A) ![\frac{182}{60} = \frac{n}{100}](/tpl/images/2453/3360/85600.png)
B) ![\frac{182}{100} = \frac{n}{60}](/tpl/images/2453/3360/53008.png)
C) ![\frac{60}{100} = \frac{128}{n}](/tpl/images/2453/3360/99333.png)
D) ![\frac{60}{128} = \frac{n}{100}](/tpl/images/2453/3360/7c74a.png)
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Let n be equal to 182% of 60. Which of the fo...
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