If a truck starts from rest and it has acceleration of 4m/s square for 5 second , calculate it's final velocity . What will be the distance travelled by the truck during the time interval​

Answers:

Final Velocity = 20 m/s

Distance Traveled = 50 meters

Explanation:

The truck starts from rest, so its initial starting velocity is 0 m/s. I'll denote this as Vi = 0.

The final velocity is what we want to find, so we want to solve for Vf.

The acceleration is a = 4 m/s^2.

The change in time is t = 5 seconds.

So,

a = (Vf - Vi)/(t)

4 = (Vf - 0)/5

4*5 = Vf

20 = Vf

Vf = 20

The final velocity is 20 m/s.

Now let's calculate the distance traveled using the following kinematics equation:

d = 0.5*(Vi+Vf)*t

d = 0.5*(0+20)*5

d = 0.5*(20)*5

d = 10*5

d = 50

The truck travels a total distance of 50 meters.

This is another way to calculate the distance traveled where we don't need to find Vf

d = Vi*t + 0.5*a*t^2

d = 0*5 + 0.5*4*5^2

d = 0 + 2*25  

d = 50

However, since your teacher wanted you to compute Vf, I think you should stick to the previous set of steps.

a.   we have two

lines:   y = 4-x   and  

y = 8-x^-1

given two simultaneous equations that are both to be

true, then the solution is the points where the lines cross. the intersection is

where the two equations are equal. therefore the solution that works for both

equations is when

4-x = 8-x^-1

this is where the two lines will cross and that is the

common point that satisfies both equations.

b.   4-x = 8-x^-1

  x           4-x       8-x^-1

-3           7        

8.33

-2           6         8.5

-1           5         9

  0           4        

-

  1           3        

7

  2           2        

7.5

  3           1         7.67

the table shows that none of the x values from -3 to 3 is

the solution because in no case does

4-x = 8-x^-1

to find the solution we need to rearrange the equation to

find for x:

4-x = 8-x^-1

multiply both sides with x:

4x-x^2 = 8x-1

x^2+4x-1=0

x= -4.236, 0.236

therefore there are two points that satisfies the

equation.

find y:  

x=-4.236

y = 4-x   = 4 – (-4.236)

= 8.236

y = 8-x^-1 =   .236)^-1

= 8.236

x=0.236

  y = 4-x   = 4 – (0.236) = 3.764

y = 8-x^-1 =   8-(0.236)^-1

= 3.764

thus the two lines cross at 2 points:

(-4.236, 8.236) & (0.236, 3.764)

c.   to solve

graphically the equation 4-x = 8-x^-1

we would graph both lines: y = 4-x   and   y

= 8-x^-1

the point on the graph where the lines cross is the

solution to the system of equations.

just graph the points on part b on a cartesian coordinate

system and extend the two lines.   the

solution is, as stated, the point where the two lines cross on the graph.

step-by-step explanation:

mark brainliest!

perimeter of the base times height

step-by-step explanation: