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Mathematics, 31.08.2021 04:10 miriam62

Given: ABCD is a parallelogram, \overline{AC} AC bisects ∠BCD and DB bisects ∠ABC.

Prove: AC ⊥ BD

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Given: ABCD is a parallelogram, \overline{AC} AC bisects ∠BCD and DB bisects ∠ABC.

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