Find the distance between the point A(2, −3) and the line with equation L : 3x−4y + 2 = 0.​

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

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idk whyy this is happening, i cant even read my notification bc i keep getting errors

~coco

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it is x equals 3   plese mark me really need it

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