PLEASE HELP ME!!! Ror what values of k will the relation not be a function S={(2-|k+1|, 4), (-6, 7)}

Step-by-step explanation:

The relation S is note a function when

2 - |k+1| = -6

Because when they are equal we have two points (-6,4) and (-6,7) in S which implies that -6 is related to two different values.

Now solving

2 - |k+1| = 6

2 - |k+1| = 6

2 - 6 = |k+1|

-4 = |k +1|

But absolute value always non negative, so there is no such k.

for this pair of functions g(x)=x-2 and f(x)=|x| is (g o f)(a)= |a| -2

step-by-step explanation:

g(x)=x-2

f(x)=|x|

(g o f)(a)=?

(g o f)(x)=g(f(x))

(g o f)(x)=g(|x|)

(g o f)(x)=|x|-2

(g o f)(a)=|a|-2